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-32x^2-288x+900=0
a = -32; b = -288; c = +900;
Δ = b2-4ac
Δ = -2882-4·(-32)·900
Δ = 198144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{198144}=\sqrt{2304*86}=\sqrt{2304}*\sqrt{86}=48\sqrt{86}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-288)-48\sqrt{86}}{2*-32}=\frac{288-48\sqrt{86}}{-64} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-288)+48\sqrt{86}}{2*-32}=\frac{288+48\sqrt{86}}{-64} $
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